Question

solve by using substitution method x-2y=2 ;3x+4y=3​

Answer 1

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x-2y= 2-----➊

3x+4y= 3----➋

From equation 1

we get ,

x= 2+2y ----❸

Now, put Equation 3 into Equation 2

=> 3x+4y=3

=> 3( 2+2y) +4y= 3

=> 6+6y+4y= 3

=> 10y+6= 3

=> 10y= 3-6= -3

=> y= -3/10

Put y's value into equation 1

=>x-2y=2

=> x-2*-3/10=2

=> x-+6/10=2

=> x+3/5=2

=>x = 2-3/5= 10-3/5

=> x= 7/5

Check:

=> x-2y= 2

Taking LHS

=> 7/5-2*-3/10

=> 7/5+6/10

=> 7/5+3/5

=> 10/5

=2

Hence,LHS = RHS

More information=>

Substitution method is a way of solving the Equation in which we convert the whole Equation into one variable form and put into another equation to find out the other variable's value.

Answer 2

Solution:   x - 2y = 2

⇒               x = 2 + 2y ---(i)

Substitute the value of x in the 2nd equation.

⇒               3x + 4y = 3

⇒               3(2 + 2y) + 4y = 3

⇒               6 + 6y + 4y = 3

⇒               6 + 10y = 3

⇒               10y = 3 - 6

⇒               10y = -3

⇒               y = -3/10

Substitute the value of y in (i).

⇒               x = 2 + 2y

⇒               x = 2 + 2 × (-3/10)

⇒               x = 2 - 3/5

⇒               x = (10 -3)/5

⇒               x = 7/5

Therefore, x = 7/5, y  = -3/10