solve by using suitable identity 103*109
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5
Answer:
we have,
(100+3) *(100+9)
11
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3
103 × 109
( 100 + 3 ) × ( 100 + 9 )
100 (100+9) + 3 (100+9)
10000+900+300+27
11207
[distributive property]
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