Question

solve by using the quadratic formula 2 upon 5 into x square minus x minus 3upon 5...?​

Answer 1

Answer:

The zeroes of the Quadratic equation (2/5)x² - x - (3/5) is 3 and (-1/2).

Step-by-step explanation:

I believe your Question is,

" (2/5)x² - x - (3/5), find its zeroes using Quadratic formula."

Now,

(2/5)x² - x - (3/5) = 0

To make all its digits a whole number, let's multiply the whole equation by 5

So, we get,

(2/5)x² × 5 - x × 5 - (3/5) × 5 = 0 × 5

2x² - 5x - 3 = 0

ax² + bx + c = 0

where a = 2, b = -5, c = -3

Using Quadratic formula,

x = (-b ± √(b² - 4ac))/2a

x = (-(-5) ± √((-5)² - 4(2)(-3))/2(2)

x = (5 ± √(25 + 24))/4

x = (5 ± √49)/4

x = (5 ± 7)/4

x = (5 + 7)/4 or (5 - 7)/4

x = 12/4 or (-2/4)

x = 3 or (-1/2)

Thus, the zeroes of the Quadratic equation (2/5)x² - x - (3/5) is 3 and (-1/2).

Hope it helped and believing you understood it........All the best.