solve by using transposition: X/4.5= 1/1.5
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Given that,
The acceleration a=8m/s2
Initial velocity u=0m/s
We know that,
The displacement in the nth second
=u+a(n−21)
Now, the displacement in 5th second
=0+8(5−21)
=36m
Hence, the distance covered by it in fifth second is 36 m
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