Solve c part of question 1 by step by step simultaneous equation
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let 1/(x+1) =a
1/(y-1) =b
we get
20a+4b=5 and 10a-4b=1
solving these two equations by elimination method
4b and -4b gets cancelled
we get
30a=6
a=6/30
a=1/5
substituting a value in one equation
20(1/5) +4b=5
4+4b=5
4b=5-4
b=1/4
we 1/(x+1) =1/5
x+1=5
x=4
1/y-1=1/4
y-1=4
y=5
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