Math, asked by Anonymous, 10 months ago

Solve (class 11) .........​

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Answered by konrad509
5

\displaystyle\\\lim_{x\to 2}\left(\dfrac{e^x-e^2}{x-2}\right)=\lim_{x\to 2}\left(\dfrac{(e^x-e^2)'}{(x-2)'}\right)=\lim_{x\to 2}\dfrac{e^x}{1}=\lim_{x\to 2}e^x=e^2

Answered by Anonymous
3

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hey dear see the attachment of

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