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Answered by
1
hey...its very simple...
sin(90-@)=cos@
cos(90-@)=sin@
therefore according to question....
sin@sin@+cos@cos@=1{ using cos^2@+sin^2@=1}
therefore answer is 1
sin(90-@)=cos@
cos(90-@)=sin@
therefore according to question....
sin@sin@+cos@cos@=1{ using cos^2@+sin^2@=1}
therefore answer is 1
Answered by
0
sin theta × cos (90-theta) + Cos theta × Sin(90-theta)
We know that Cos (90-theta) = Sin theta and Sin(90-theta) = Cos theta
SIN THETA × COS (90-THETA) + COS THETA × SIN (90-THETA)
SIN THETA × SIN THETA + COS THETA × COS THETA
SIN²THETA + COS² THETA
We know that sin² theta + Cos² theta = 1...
THEREFORE,
option (c) is right answer
We know that Cos (90-theta) = Sin theta and Sin(90-theta) = Cos theta
SIN THETA × COS (90-THETA) + COS THETA × SIN (90-THETA)
SIN THETA × SIN THETA + COS THETA × COS THETA
SIN²THETA + COS² THETA
We know that sin² theta + Cos² theta = 1...
THEREFORE,
option (c) is right answer
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