solve completing square method plzzz
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2x^2 - 6x - 4
2x^2 - 4x - 2x - 4
2x (x - 2) 2(x - 2)
( 2x + 2) ( x- 2)
sanket3183:
solve in book
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2x^2-6x-4=0
dividing whole equation by 2
x^2-3x-2=0
x^2-3x+(3/2)^2-(3/2)^2-4=0
[x-(3/2)]^2=(3/2)^2+4
[x-(3/2)]^2=9/4+4
=(9+16)/4
=25/4
x-3/2=±5/2
x=±5/2+3/2
x=8/2 or -2/2
x=4 or -1
dividing whole equation by 2
x^2-3x-2=0
x^2-3x+(3/2)^2-(3/2)^2-4=0
[x-(3/2)]^2=(3/2)^2+4
[x-(3/2)]^2=9/4+4
=(9+16)/4
=25/4
x-3/2=±5/2
x=±5/2+3/2
x=8/2 or -2/2
x=4 or -1
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