Math, asked by shivamjadhao1598, 2 months ago

solve = cos 28°/sin62°​

Answers

Answered by vansh8584
1

Answer:

1

Step-by-step explanation:

cos28⁰/sin62⁰

{cos(90-A)=sinA}

sin(90-62)/sin62⁰

sin62⁰/sin62⁰

=1

Answered by AbhinavRocks10
5

➠\frac{cos28°}{sin62°}

sin62°

cos28°

Formula to be used:-

cos(90°-θ) = sinθ

Solution :-

\begin{gathered} = > \frac{cos28°}{sin62°} \\ = > \frac{cos(90° - 62°)}{sin62°} \\ = > \frac{sin62°}{sin62°} \\ = > 1\end{gathered}

=> sin62°

⟹ cos28°

=> sin62°

⟹ cos(90°−62°)

=> sin62°

=>sin62°

Hence, your answer is 1.

Find value of :-

→\frac{cos28°}{sin62°} sin62°cos28°

Formula to be used:-

cos(90°-θ) = sinθ

Solution :-

\begin{gathered} = > \frac{cos28°}{sin62°} \\ = > \frac{cos(90° - 62°)}{sin62°} \\ = > \frac{sin62°}{sin62°} \\ = > 1\end{gathered}

=> sin62°

⟹ cos28°

=>sin62°

⟹ cos(90°−62°)

=> sin62°

➠sin62°

=>1

Hence, your answer is 1.

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