Math, asked by nara615, 1 year ago

solve cos 3x+cos x-cos 2x=0?

Answers

Answered by Anonymous
144
Hello
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cos 3x + cos x - cos 2x                            = 0 
[cos 3x + cos x ] - cos 2x                         = 0 
2 cos [(3x + x)/2] .cos [(3x-x)/2] - cos 2x = 0 
2 cos 2x . cos x  - cos 2x                         = 0 
cos 2x  [ 2 cos  x  - 1 ]                             = 0 
cos 2x  = 0  or cos x = 1/2                       = cos π/3
2x = (2n +1 )π/2 or x = 2mπ +- π/3
x = (2n + 1 ) π/4 or x = 2mπ +- π/3 ; where  n , m ∈ I
Answered by RajeshKumarNonia
63
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