solve cos 40°+cos 80°+cos 160°
Answers
Answer:
0
Step-by-step explanation:
Formula to be applied : cosA+cosB= 2cos(A+B/2).cos(A-B/2)
cos40+cos80+cos120= 2cos(80+40/2).cos(80-40/2) + cos(160)
=2cos(180/2).cos(40/2) + cos(160)
=2cos(60).cos(20) +cos(160)
= 2(1/2). cos(20) + cos(160) [Since cos(60)=1/2]
=cos(20) + cos(160)
=2cos(160+20/2).cos(160-20/2)
=2cos(90).cos(70) [Since cos(90)=0]
=0
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cos 40=cos (60-20)=cos 60 cos 20+sin 60 sin20
cos 80= cos (60+20)=cos 60 cos 20- sin 60 sin 20
cos 160=cos (180-160)= -cos 20
cos 240=cos (180+60)=-cos 60=-1/2
in second quant sin is positive
3rd quant tan is positive
sub all
cos 60 cos 20 + sin 60 sin 20+ cos 60 cos 20 - sin 60 sin 20-cos 20-1/2
= 2cos 60 cos 20- cos 20 -1/2
=cos 20(2(1/2)-1)-1/2
cos 20(0)-1/2
ans=-1/2