Math, asked by biswasdebdulal, 1 month ago

solve cos(50°+ A ) = sin (30°+ A)
pls solve​

Answers

Answered by Thundersoul
2

Answer:

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Answered by tennetiraj86
1

Answer:

Solution :-

Method-1:-

Given that

Cos (50°+A) = Sin (30°+A)

We know that

Cos (90° - A) = Sin A

=> Cos (50°+A) = Cos [90°-(30°+A)]

=> Cos (50°+A) = Cos (90°-30°-A)

=> Cos (50°+A) = Cos (60°-A)

=> 50°+A = 60°-A

Since A is acute angle

=> A+A = 60°-50°

=> 2A = 10°

=> A = 10°/2

=> A = 5°

Therefore, A = 5°

Method -2 :-

Given that

Cos (50°+A) = Sin (30°+A)

We know that

Sin (90° - A) = Cos A

=> Sin [90°-(50°+A) ]= Sin (30°+A)

=> Sin (90°-50°-A) = Sin (30°+A)

=> Sin (40°-A) = Sin (30°+A)

=> 40°-A = 30°+A

Since A is acute angle

=> A+A = 40°-30°

=> 2A = 10°

=> A = 10°/2

=> A = 5°

Therefore, A = 5°

Answer:-

The value of A for the given problem is 5°

Check:-

If A = 5° then

LHS = Cos (50°+A)

=> LHS = Cos (50°+5°)

=> LHS = Cos 55°

=> LHS = Cos (90°-35°)

=> LHS = Sin 35°

and

RHS = Sin (30°+A)

=> RHS = Sin (30°+5°)

=> RHS = Sin 35°

LHS = RHS is true for A = 5°

Verified the given relations in the given problem

Used formulae:-

→Sin (90° - A) = Cos A

→Cos (90° - A) = Sin A

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