solve :- cos¢ + sin¢ = √2 , then the value of ¢ is
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cos 45+sin 45
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Hey !!
⏭ cos¢ + sin¢ = √2
cos¢/√2 + sin¢/√2 = √2/√2 (°•° divided throughout by √2)
cos¢×cos45° + sin¢ × sin45° = 1
•°• cosA ×cosB + sinA×sinB = cos(A-B)
similarly
=> cos(¢ - 45° ) = 1
= cos(¢ - 45° ) = cos0°
= ¢ = 45° =π/4
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Hope it helps you !!!
#Rajukumar111
⏭ cos¢ + sin¢ = √2
cos¢/√2 + sin¢/√2 = √2/√2 (°•° divided throughout by √2)
cos¢×cos45° + sin¢ × sin45° = 1
•°• cosA ×cosB + sinA×sinB = cos(A-B)
similarly
=> cos(¢ - 45° ) = 1
= cos(¢ - 45° ) = cos0°
= ¢ = 45° =π/4
◀◀◀◀◀◀◀◀◀◀◀◀
Hope it helps you !!!
#Rajukumar111
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