solve cos theta +√3sin theta= 2
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Solution :
Here I am using A instead of theta.
cosA + √3sinA = 2
divide each term with 2 , we get
(1/2)cosA + (√3/2)sinA = 1
=> sin30°cosA + cos30°sinA = 1
=> sin(30+A) = sin 90°
=> 30 + A = 90°
=> A = 90 - 30
=> A = 60°
••••
Here I am using A instead of theta.
cosA + √3sinA = 2
divide each term with 2 , we get
(1/2)cosA + (√3/2)sinA = 1
=> sin30°cosA + cos30°sinA = 1
=> sin(30+A) = sin 90°
=> 30 + A = 90°
=> A = 90 - 30
=> A = 60°
••••
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