Solve cos√x derivative by first principle_??
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Answer:
f′(x)=h→0limhf(x+h)−f(x)
=h→0limhcos(x+h)−cosx
=h→0lim[hcosxcosh−sinxsinh−cosx]
=h→0lim[h−cosx(1−cosh)−sinxsinh]
=h→0lim[h−cosx(1−cosh)=hsinxsinh]
=−cosx(h→0limh1−cosh)−sinxh→0lim(hsinh)
=−cosx.(0)−sinx(1)=−sinx
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