solve cos x dy=y(sinx-y)dx
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cosx dy= y(sinx -y)dx
dy/y = tanx dx – ydx
integrating on both sides we get
ln y= -ln cosx-xy+c
(y/cos x)=e-xy+c
dy/y = tanx dx – ydx
integrating on both sides we get
ln y= -ln cosx-xy+c
(y/cos x)=e-xy+c
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