solve cos°40A=sin°50A then find the value of A
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Answered by
1
cos40°A = sin50°A
cos(90° - 50°)A = sin50°A
sin50°A = sin50°A
So that A can be any value.....
Hope its Help you...:))
thnks...
cos(90° - 50°)A = sin50°A
sin50°A = sin50°A
So that A can be any value.....
Hope its Help you...:))
thnks...
kunalssagar200p6kgce:
thnx
Answered by
0
Cos 40 A° = Sin 50 A°
We know that Cos A = Sin (90-A)
Cos (90-50 A)° = Sin 50 A°
Sin 50 A° = Sin 50 A°
_______________________________________________________
And so A can be of any value as they are independent of the values.
_______________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
We know that Cos A = Sin (90-A)
Cos (90-50 A)° = Sin 50 A°
Sin 50 A° = Sin 50 A°
_______________________________________________________
And so A can be of any value as they are independent of the values.
_______________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
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