Question

Solve cosec theta-cot theta=√3

Answer 1

=> cosec A - cot A = √3 ----(1)

=> We know that,
cosec²A - cot²A = 1
(cosec A - cot A)(cosec A + cot A) = 1
(cosec A+ cot A) (√3) = 1
cosec A + cot A = 1/√3 ----(2)


(1) + (2)

cosec A - cot A + cosec A + cot A = √3 + 1/√3
2cosec A = 3+1/√3
2cosec A = 4/√3
cosec A = 4/2√3
cosec A = 2/√3
cosec A = cosec 60°

A = 60°

[Here,I took θ = A]