Question

solve : cosec theta - cot theta = root 3

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portion : 11 th std trigonometry maths (creative question)​

Answer 1

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Answer 2

Hi ,

According to the problem given,

CosecX + CotX = √3 -----( 1 )

We know that ,

Cosec² X - Cot² X = 1

( CosecX + Cot X )(CosecX - CotX) =1

[ Since a² - b² = ( a + b ) ( a - b ) ]

( √3 ) ( CosecX - CotX ) = 1 from ( 1 )

CosecX - CotX = 1 / √3 -----( 2 )

Add equations ( 1 ) and ( 2 ) we get,

2CosecX = √3 + 1 /√3

= ( 3 + 1 ) / √3

= 4 / √3

Therefore,

CosecX = 4 /2√3

CosecX = 2 / √3

CosecX = Cosec 60°

X = 60°

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