Math, asked by aryamansingh2004, 6 months ago

solve cotx-cot2x=2. find the value of x

Answers

Answered by Ranveerx107

2

$\huge\fcolorbox{aqua}{cyan}{\huge\underline{Answer}}$

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Answered by zeenat82

0

Answer:

L.H.S.=cotx-cot2x=

cosx

sinx

-

cos2x

sin2x

=

cosxsin2x-cos2xsinx

sinxsin2x

=

sin(2x-x)

sinxsin2x

=

sinx

sinxsin2x

When, x=15∘

1

sin2x

=

1

sin30∘

=2=R.H.S.

So, given equation is true for x=15∘

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