solve (D^2+3D+2)y=0
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Answered by
2
Answer:
Given differential equation is
(D² - 3D + 2)y = 0
Auxiliary equation of above differential equation is
D² - 3D + 2 = 0
=> D² - 2D - D + 2 = 0
=> D(D - 2) - 1(D - 2) = 0
=> (D - 2)(D - 1) = 0
=> D = 2,1
Hence the general solution is given by
y = c₁e²ˣ + c₂eˣ
Answered by
4
Given,
A differential equation (D²+3D+2)y = 0
To Find,
The solution of this differential equation.
Solution,
The given differential equation is
(D² +3D + 2)y = 0
Now, The auxiliary equation of above differential equation is
D² + 3D + 2 = 0
D² + 2D + D + 2 = 0
D(D + 2) + 1(D + 2) = 0
(D + 2)(D + 1) = 0
D = -2 or -1
Now, the general solution is given by
y = c₁e⁻²ˣ + c₂e⁻ˣ
Hence, the general solution of the differential equation is y = c₁e⁻²ˣ + c₂e⁻ˣ.
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