Question

solve : d^2/dt^2+4dy/dt-5y=5 given that y=0,dy/dt=2 when t=0​

Answer 1

Step-by-step explanation:

let d/dt=D

(D^2+4D-5)y=5

the auxiliary eq. is m2+4m-5=0

(m-5)(m-1)=0

m=5,1

c. f.=c1e^x+c2e^5x

p. I.=5/D2+4D-5

=5/0+0-5

=5/-5

=-1

p. I.=-1

y

thus y=c. f.+p. I.

I. e. y=c1e^x+c2e^5x-1ans.