Question

Solve: d/dt(2t^10 + 10t^2+5t in derivation formula​

Answer 1

Explanation:

hope it helps..

Good luck

Answer 2

Answer:

$\frac{d}{dt} (2 {t}^{10 } + 10 {t}^{2} + 5t) \\ \\ \\ = 2.10. {t}^{10 - 1} + 2.10. {t}^{2 - 1} + 5. {t}^{1 - 1} \\ \\ \\ = 20 {t}^{9} + 20t + 5 {t}^{0} \\ \\ \\ = 20 {t}^{9} + 20t + 5 \\ \\ \\ formula \: \: \: \: - \: \: \: \: \frac{d}{dx} ( {x}^{m} ) = {x}^{ m- 1} \\ \\ x {}^{0} = 1$