solve D power 4-3D cube-2D square )y is equal to 0
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(D^4-3D^3-2D^2)y=0 then y=0,or (D^2-3D-2)y=0, D=1,D=1/2
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(D^4-3D^3-2D^2)Y=0
(D^4-3D^3-2D^2)=0,Y=0
D^2(D^2-3D-2)=0,Y=0
D^2-3D-2=0,Y=0
WE KNOW THAT AX^2+BX+C=0
=-B+or-((B^2-4AC)/2A)
=-(-3)+or-((9-4(-2))/2
=+3+or-(17/2)
=3+8.5. or =3-8.5
D=11.5. D=-5.5
(D^4-3D^3-2D^2)=0,Y=0
D^2(D^2-3D-2)=0,Y=0
D^2-3D-2=0,Y=0
WE KNOW THAT AX^2+BX+C=0
=-B+or-((B^2-4AC)/2A)
=-(-3)+or-((9-4(-2))/2
=+3+or-(17/2)
=3+8.5. or =3-8.5
D=11.5. D=-5.5
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