Question

solve (D² +4) y =cos3xcox​

Answer 1

Answer:

The differential equation whose solution is y=acos(3x+b) is?

y=acos(3x+b)

Differentiating both sides, we get

⇒y

1

=−3asin(3x+b)

⇒y

2

=−9acos(3x+b)

⇒y

2

=−9y

⇒y

2

+9y=0

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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