Question

Solve (D2+4)y=sinx+ex+x2

Answer 1

Answer:

(D+1)(D+3)y=e

−x

sinx+xe

3x

C.F. = C

1

e

−x

+C

2

e

−3x

For P.I. , we get

D

2

+4D+3

e

−x

sinx+xe

3x

e

−x

D(D+2)

sinx

+e

3x

(D+4)(D+6)

x

e

−x

D(D

2

−4)

(D−2)sinx

+e

3x

24

24

(D

2

+10D)

+1

x

=e

−x

−3

(sinx+2cosx)

+e

3x

288

5

Answer 2

Answer:

D2y+4y=sinx+ex+x2 question is solved