Math, asked by Deepjyoti3717, 11 months ago

solve d2y/dxsquar=xsinx​

Answers

Answered by apurvaa200297
2

y=xsinx

dy/dX=x(d/dx(sinx))+ sinx(d/dx(X))=xcosx + sinx(1)= sinx + xcosx

d ^{2} y \div dx  = ^{2}

[d/dx(X)]cosx+X[d/dx(cosx)] + d/dX(sinx)= cosx + X(-sinx) + cosx= 2 COSX- XSINX

Answered by riteshraghav89
0

Answer:

do to check answer brother

Attachments:
Similar questions