Question

solve differential equation (1+x)ydx+ (1-y)xdy = 0
full explained solution​

Answer 1

Answer:

Step-by-step explanation:

(1+x)ydx+ (1-y)xdy = 0

(1+x)ydx =  (y-1)xdy

( (1+x) /x )dx = ( (y-1) / y )dy

$\int {((1/x)+1)} \, dx$  = $\int {(1-(1/y))} \, dy$

㏑x + x =  y- ㏑y +c

㏑(xy) + x - y = c                                  c is integral constant