solve differential equation DY by DX + y by x equal y square
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Answer: y^2 - y/x - 1 = 0
Step-by-step explanation:
d(y)/d(x) + y/x = y^2
∫d(y)/d(x)×d(x) = ∫y^2 - ∫y/x
∫d(y) = y^3/3 - ∫y/x
y - y^3/3 = -1 × ∫y/x
y^3/3 -y = ∫y/x
taking derivatives on sides gives
1/3×3×y^2 - 1 = y/x
y^2 - y/x - 1 =0
This is the equation we get after solving.
Tried hard on this so please mark as brainliest answer.
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