Question

solve differential equation
dy/dx=√1-y²/√1-x²​

Answer 1

Step-by-step explanation:

dy/dx+ whole √ 1-y^/1-x^ = 0

dy/dx =whole √ 1+y^/1+x^

dy/√1-y^ = dx/√1+x^

Integrating both the sides

f dy/ √1-y^ = f dx/√1-x^

sin-1 y = -sin-1 x + c

sin-1 x + sin-1 y =c