Question

solve differential equation y=sin p-p cos p?​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Solve,

$y=\sin p-p\cos p$

differentiating the given equation with respect $x$, we get

$\sin p \text{ dp}=dx$

Integrating we have,

$\cos p=c-x$

From the given equation we also get,

$p\cos p=\sin p-y\\\\\Rightarrow p\cos p=\sqrt{1-\cos^2p}-y\\\\\Rightarrow p=\frac{\sqrt{1-\cos^2p}-y}{\cos p}\\\\\Rightarrow c-x=\cos(\frac{\sqrt{1-(c-x)^2}-y}{c-x})\\\\\Rightarrow c-x=\cos(\frac{\sqrt{1-c^2+2cx-x^2}-y}{c-x})$