Question

Solve dy/dx+2xy=ex2​

Answer 1

Answer:

Step-by-step explanation:

Here is the equation: dydx−2xy=ex2

And my solution

P(x)=−2x⟹I(x)=e−x2

I(x)∗dydx−2xyI(x)=ex2I(x)

e−x2dydx−2xye−x2 = ex2e−x2

d(−2yx)dx=ex2e−x2

Since ex2∗e−x2=e0=1

Therefore, −2yx=1+c

If I'm doing something wrong, please show me! Thanks!

ordinary-differential-equations