Question

Solve :
dy/DX -2y/x = y⁴​

Answer 1

Answer:

1/y^4*dy/dx-2/xy^3=1

1/y^3=v

(-3/y^4)dy/dx=dv/dx

(-1/3)dv/dx- 2v/x=1

I.T=e^integrate(6dx/x)=x^6

v*x^6=-3 integrate (x^6*dx+k)

=-3x^7/7+k

x^6(3x+7/y^3)=k