Question

solve each equation by factoring3K^-18K-21=0​

Answer 1

$\huge \bold\color{red}{\boxed {\boxed{☆Answer☆}}}$

$\bold\color{brown}=> 3k² - 18k - 21$

$\bold\color{brown}=> 3k² -21k + 3k - 21$

$\bold\color{brown}=> 3k(k-7) + 3(k-7)$

$\bold\color{green}{\boxed{=> (3k+3)(k-7)}}$

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I hope it will help you........

Answer 2

Answer k =(6-√64)/2=3-4= -1.000

STEP 1 Equation at the end of step 1 (3k2 -18k) -21= 0

STEP 3 Pulling out like terms 3.1 then Pull out like factors 3k2 - 18k - 21  =   3 • (k2 - 6k - 7) Trying to factor by splitting the middle term 3.2 Factoring  k2 - 6k - 7 The first term is,  k2  its coefficient is  1 . The middle term is,  -6k  its coefficient is  -6 .The last term, "the constant", is  -7  Step-1 : Multiply the coefficient of the first term by the constant   1 • -7 = -7 Step-2 : Find two factors of  -7  whose sum equals the coefficient of the middle term, which is -6 -7 + 1=-6 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -7  and  1 k2 - 7k + 1k - 7 Step-4 : Add up the first 2 terms, pulling out like factors k •(k-7) Add up the last 2 terms, pulling out common factors :1 • (k-7 Step-5 : Add up the four terms of step 4 : (k+1)•(k-7) Which is the desired factorization Equation at the end of step 3 3 • (k + 1) • (k - 7)  = 0 STEP 4 Theory - Roots of a product 4.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now solve each term = 0 separately In other words, we are going to solve as many equations as there are terms in the product Any solution of term = 0 solves product = 0 as well.Equations which are never true:4.2 Solve:3=0 This equation has no solution.A a non-zero constant never equals zero.Solving a Single Variable Equation: 4.3Solve:k+1 = 0 Subtract  1  from both sides of the equation : k = -1