Question

Solve each equation: (i) 3a + 2 = 11 (ii) 17 = 3(y-5) + 8​

Answer 1

Answer:

$1) \: 3a + 2 = 11 \\ \\ = > 3a = 11 - 2 \\ \\ = > 3a = 9 \\ \\ = > a = \frac{9}{3} \\ \\ = > a = 3 \\ \\ 2) \: 17 = 3(y - 5) + 8 \\ \\ = > 17 = 3y - 15 + 8 \\ \\ = > 17 = 3y - 7 \\ \\ = > 17 + 7 = 3y \\ \\ = 24 = 3y \\ \\ = > \frac{24}{3} = y \\ \\ = > 8 = y \\ \\ or \: y \: = 8$

hope it helps uH :)