Question

solve each of the following?
2z²-3z-14=0​

Answer 1

Answer:

z = -2, 7/2

Step-by-step explanation:

By splitting the middle term we get:-

$= > 2 {z}^{2} - 3z \: - 14$

$= > 2 {z}^{2} + 4z \: - 7z - 14$

$= > 2z(z + 2) - 7(z + 2)$

$= > (2z - 7)(z + 2)$

$= > z = - 2 \: or \: \frac{7}{2}$

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Answer 2

Solution:

Given equation,

→ 2z² - 3z - 14 = 0

We have to find out the values of z.

By splitting the middle term, we get,

→ 2z² - 7z + 4z - 14 = 0 (-7 + 4 = -3 and -7 × 4 = -28)

→ z(2z - 7) + 2(2z - 7) = 0

→ (z + 2)(2z - 7) = 0

By zero product rule,

→ Either z + 2 = 0 or 2z - 7 = 0

→ z = -2, 7/2

→ z = -2, 3.5

★ So, the values of z are -2 and 3.5

Answer:

• z = -2, 3.5

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