Question

solve each of the following equation and chek your answer in each case..

Answer 1

$\frac{2x + 3}{3} - \frac{3x - 2}{4} = 1 \\ = \frac{4(2x + 3) - 3(3x - 2)}{12} = 1 \\ = \frac{8x + 12 - 9x + 6}{12} = 1 \\ = - x + 18 = 12 \\ = - x = 12 - 18 \\ = - x = - 6 \\ = x = 6 \\ \\ x = 6 \: \: answer.....$
chek....

2x+3/3 -3x-2/4 =1
=2*6+3/3 -3*6-2/4 =1
=12+3/3 -18-2/4=1
=15/3 -16/4 = 1
=5-4 =1
=1=1
L. H. S. =R. H. S...
PROVED.....

6 is the right answer....

Answer 2

2x + 3/3 - 3x - 2/4 = 1

LCM: 12

4(2x + 3/3) - 3(3x - 2/4) = 1

8x + 12/12 - 9x + 6/12 = 1

-1x + 18/12 = 1

-1x + 18 = 1*12

-1x + 18 = 12

-1x = 12 - 18

-1x = -6

x = -6/-1

x = 6

Proof: Substituting the value of x in each term:

2x + 3/3 - 3x - 2/4 = 1

2*6 + 3/3 - 3*6 - 2/4 = 1

12 + 3/3 - 18 - 2/4 = 1

LCM: 12

4(12 + 3/3) - 3(18 - 2/4) = 1

48 + 12/12 - 54 + 6/12 = 1

12/12 = 1

1 = 1

Hence proved.

Hope it helps :)