Math, asked by sakshisharma30966, 11 months ago

Solve each of the following equation for real x and y (1). ( x+yi). + (3-2i) = 1+4i​

Answers

Answered by Sbscalok
3

Answer:

x = -2 , y = 6

Step-by-step explanation:

(x+ yi) + (3 - 2i) = 1 + 4i

(x+3) + (y-2)i = 1 + 4i

comparing both side of real and imaginary part

x + 3 = 1. and. y - 2 = 4

x = -2. and. y = 6

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