Math, asked by sandhyaranibehera080, 7 months ago

solve each of the following equations : 1,(x-2)+(x-3)+(x-a) =0. 2,3(2x-3)=4(2x+4).​

Answers

Answered by tbasu6790
2

Answer:

1. (5+a)/3

2. -25/2 or -12.5

Step-by-step explanation:

1. (x-2)+(x-3)+(x-a)=0

=> x-2+x-3+x-a =0

=> 3x-5-a =0

=> 3x=5+a

=> x = (5+a)/3

2. 3(2x-3) = 4(2x+4)

=> 6x- 9 = 8x + 16

=> 2x = -25

=> x = -25/2

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