Math, asked by vvsns2301, 6 months ago

Solve each of the following equations by trial – and – error method:
(i) x + 3 =12
(ii) x -7 = 10
(iii) 4x = 28
(iv) (x/2) + 7 = 11
(v)3x-5=13

(vi) 5x-23 = 16 ​

Answers

Answered by alex971
2

Answer:

i)x= 9

ii)x= 17

iii)x= 7

iv)x= 8

v)x= 6

vi)x= 39/5

Step-by-step explanation:

i) x= -3+12

x= 9

ii) x= 7+10

x= 17

iii) 4x= 28

x= 28/4

x= 7

iv) x/2= -7+11

x/2= 4

x= 8

v) 3x-5= 13

3x= 5+13

3x= 18

x= 18/3

x= 6

vi) 5x-23=16

5x= 23+16

5x= 39

x= 39/5

Please mark me as brainliest it took me a lot of time

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