Solve, each of the following equations, using the formula: x square +6x-10=0 plz plz plz answr......step by step answr....
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Answered by
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Answer:
Hey mate here is your answer:
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→![x^2+6x-10=0. x^2+6x-10=0.](https://tex.z-dn.net/?f=x%5E2%2B6x-10%3D0.)
We know that:
→![x=\frac{-b+-\sqrt{b^2-4ac} }{2a}, x=\frac{-b+-\sqrt{b^2-4ac} }{2a},](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B-%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D%2C)
∴,
→![x=\frac{-6+-\sqrt{6^2-4*1*-10} }{2*1}, x=\frac{-6+-\sqrt{6^2-4*1*-10} }{2*1},](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-6%2B-%5Csqrt%7B6%5E2-4%2A1%2A-10%7D+%7D%7B2%2A1%7D%2C)
→
,
→
,
→
,
→
,
→→→
or 3±√19 is the answer.(+- means ± only).
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Hope it helps you.
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