Question

solve each of the following pairs of equation by reducing them to a pair of linear equation x/3+y/4=4 , 5x/6-y/8=4​

Answer 1

Answer:

X=6, Y= 8

Step-by-step explanation:

X/3+y/4=4 => 4x+3y/12= 4 => 4x+3y=12*4

4x+3y= 48 consider it as equation 1

5x/6-y/8 =4 => 20x-3y/24 =4 => 20x-3y = 24*4

20x-3y= 96 consider it as equation 2

Adding 2 equations

4x+3y= 48

20x-3y = 96

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(+) (+) (+)

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24x = 144

X = 144/24

X= 6

Substitute x value in equation 1

4x+3y= 48 => 4(6)+3y= 48 => 24+3y=48

=> 3y =48-24 => 3y = 24 => y = 24/3

Y= 8

X=6; Y=8 substitute in equation 1

X/3+y/4 = 4 => (6/3)+ (8/4) = 4 => 2+2 =4 => 4=4

Hence proved