Question

Solve each of the following quadratic equation
$(2x - 3)(3x + 1) = 0$
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Answer 1

Answer:

$(2x - 3)(3x + 1) = 0 \\ \\ = > 6 {x}^{2} + 2x - 9x - 3 = 0 \\ \\ = > 6 {x}^{2} - 7x - 3 = 0 \\ \\ = > 6 {x}^{2} - (9 - 2)x - 3 = 0 \\ \\ = > 6 {x}^{2} - 9x + 2x - 3 = 0 \\ \\ = > 3x(2x - 3) + 1(2x - 3) = 0 \\ \\ = > (3x + 1)(2x - 3) = 0 \\ \\ either \: 3x + 1 = 0 \\ \\ = > x = \frac{ - 1}{3} \\ \\ or \: 2x - 3 = 0 \\ \\ = > x = \frac{3}{2}$

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Answer 2

Answer:

x= 3/2, -1/3

Step-by-step explanation:

(2x-3)(3x+1)=0

2x-3 =0 or 3x+1 =0

x=3/2 or -1/3