Question

Solve each of the following quadratic equations:
5. (2x - 3)(3x + 1) = 0
6. 4x² + 5x = 0​

Answer 1

Answer:

⭐Question:-1

(2x - 3)(3x + 1) = 0

☯️Answer:-

1. $(2x - 3)(3x + 1) = 0$

$= > \: 2x - 3 = 0 \: or \: 3x + 1 = 0$

$= > \: 2x = 3 \: or \: 3x + 1= 0$

$= \geqslant x = \frac{3}{2 \: } \: or \: x = - \frac{1}{3}$

$hence \: the \: roots \: of \: the \: given \: question \: \\ are \: \frac{3}{2} \: and \: - \frac{1}{3}$

⭐Question:-2

4x² + 5x = 0

☯️Answer:-

2. $we \: have \: 4x {}^{2} + 5x = 0$

$= > x \: (4x + 5) = 0$

$= > \: either \: x = 0 \: or \: 4x + 5 = 0$

$= > x = 0 \: or \: 4x + 5 = 0$

$= > x = 0 \: or \: x = \frac{ - 5}{4}$

$thus,\:$

$x = 0 \: and \: x = \frac{ - 5}{4} \: are \: two \: roots \: of \\ equation \: 4x {}^{2} + 5x = 0$

Answer 2

Step-by-step explanation:

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