Question

solve each of the following system of equation by the method of substitution 7x-2y=1 ; 3x+4y=15​

Answer 1

Answer:

so in this question  

7x−2y=1

3x+4y=15

so first multiply the first equation by 2

We get 14x−4y=2

now add the first and second equations

14x−4y+3x+4y=15+2

17x=17

so x=1

put x in any equation get y

y=3

x=1     y=3

Hope this helps you!!!

Answer 2

7x -2y= 1.

Step-by-step explanation:

x=1/7+2y. 3x+4y=15 Value of x we will put 3(1/7+2y)-4y =15. 3/7+6y-4y=15. 3/7 +2y = 15. 2y =15*3/7. 2y = 45 /7. y= 45 /14 x=1/7+2*45/14=1/7+45/7=46/7