solve each of the following system of equation by the method of substitution 2x=3y;2x+3y=30
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Answer:
We have,
2x+3y=9 ……. (1)
3x+4y=5 …… (2)
Now,
y=
3
9−2x
On putting the value of y, in equation (2), we get
3x+4(
3
9−2x
)=5
3x+
3
36−8x
=5
9x+36−8x=15
x=15−36
Now, put the value of x in equation (1), we get
y=
3
9−2(−21)
y=
3
9+42
y=
3
51
=17
Hence, this is the answer.
Step-by-step explanation:
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