Math, asked by StarTbia, 1 year ago

Solve each of the following system of equations by elimination method.

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Answered by rohitkumargupta
9
HELLO DEAR,

8x - 3y = 5xy--------------( 1 )
6x - 5y = -2xy------------( 2 )

from--------( 1 ) & --------( 2 )
multiply by (3) in----( 1 ) by (4) in-----( 2 )

24x - 9y = 15xy
24x - 20y = -8xy
-------------------------
11y = 23xy

x = 11/23 [ put in-----( 1 )]

8(11/23) - 3y = 5(11/23)y

88/23 - 3y = 55y/23

88/23 = (55y + 69y)/23

88 = 124y

y = 22/31 , x = 11/23

I HOPE ITS HELP YOU DEAR,
THANKS

Anonymous: oh!!
Answered by Anonymous
4
✴✴ Hey friends!!✴✴.

--------------------------------------------------------

✴✴ Here is your answer↓⬇⏬⤵

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

▶⏩ By elimination method:-)

→Let ,

=> 8x - 3y = 5xy.................(1).

=> 6x - 5y = -2xy...............(2).

▶⏩ Multiply equation (1) by 5 and equation (2) by 3.

→ From equation (1)

↪➡ 5 ( 8x - 3y = 5xy ).

↪➡ 40x - 15y = 25xy..............(3).

→ From equation (2).

↪➡ 3 ( 6x - 5y = -2xy ).

↪➡ 18x - 15y = -6xy...............(4).

▶⏩ Now,
→ Substract in equation (3) and (4).

↪➡ ( 40x - 15y ) - ( 18x - 15y ) = ( 25xy ) - ( -6xy ).

↪➡ 40x - 15y - 18x + 15y = 25xy + 6xy.

↪➡ 22x = 31xy.

↪➡ y = 22x/31x.

↪➡ y = 22/31.

▶⏩ Put the value of ‘y’ in equation (1).

↪➡ 8x - 3(22/31) = 5xy.

↪➡8x - 66/31 = 5x(22/31).

↪➡ 8x - 110x/31 = 66/31.

↪➡ 138x/31 = 66/31.

↪➡ 138x = 66.

↪➡ x = 66/138.

↪➡ x = 33/69.

✔✔ Hence, the value of ‘x’ = 33/69.

and ‘y’= 22/31 ✅✅.

✴✴ Thanks!!✴✴.

☺☺☺ Hope it is helpful for you ✌✌✌.

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