Solve each of the following system of equations by elimination method.
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HELLO DEAR,
8x - 3y = 5xy--------------( 1 )
6x - 5y = -2xy------------( 2 )
from--------( 1 ) & --------( 2 )
multiply by (3) in----( 1 ) by (4) in-----( 2 )
24x - 9y = 15xy
24x - 20y = -8xy
-------------------------
11y = 23xy
x = 11/23 [ put in-----( 1 )]
8(11/23) - 3y = 5(11/23)y
88/23 - 3y = 55y/23
88/23 = (55y + 69y)/23
88 = 124y
y = 22/31 , x = 11/23
I HOPE ITS HELP YOU DEAR,
THANKS
8x - 3y = 5xy--------------( 1 )
6x - 5y = -2xy------------( 2 )
from--------( 1 ) & --------( 2 )
multiply by (3) in----( 1 ) by (4) in-----( 2 )
24x - 9y = 15xy
24x - 20y = -8xy
-------------------------
11y = 23xy
x = 11/23 [ put in-----( 1 )]
8(11/23) - 3y = 5(11/23)y
88/23 - 3y = 55y/23
88/23 = (55y + 69y)/23
88 = 124y
y = 22/31 , x = 11/23
I HOPE ITS HELP YOU DEAR,
THANKS
Anonymous:
oh!!
Answered by
4
✴✴ Hey friends!!✴✴.
--------------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
▶⏩ By elimination method:-)
→Let ,
=> 8x - 3y = 5xy.................(1).
=> 6x - 5y = -2xy...............(2).
▶⏩ Multiply equation (1) by 5 and equation (2) by 3.
→ From equation (1)
↪➡ 5 ( 8x - 3y = 5xy ).
↪➡ 40x - 15y = 25xy..............(3).
→ From equation (2).
↪➡ 3 ( 6x - 5y = -2xy ).
↪➡ 18x - 15y = -6xy...............(4).
▶⏩ Now,
→ Substract in equation (3) and (4).
↪➡ ( 40x - 15y ) - ( 18x - 15y ) = ( 25xy ) - ( -6xy ).
↪➡ 40x - 15y - 18x + 15y = 25xy + 6xy.
↪➡ 22x = 31xy.
↪➡ y = 22x/31x.
↪➡ y = 22/31.
▶⏩ Put the value of ‘y’ in equation (1).
↪➡ 8x - 3(22/31) = 5xy.
↪➡8x - 66/31 = 5x(22/31).
↪➡ 8x - 110x/31 = 66/31.
↪➡ 138x/31 = 66/31.
↪➡ 138x = 66.
↪➡ x = 66/138.
↪➡ x = 33/69.
✔✔ Hence, the value of ‘x’ = 33/69.
and ‘y’= 22/31 ✅✅.
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
--------------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
▶⏩ By elimination method:-)
→Let ,
=> 8x - 3y = 5xy.................(1).
=> 6x - 5y = -2xy...............(2).
▶⏩ Multiply equation (1) by 5 and equation (2) by 3.
→ From equation (1)
↪➡ 5 ( 8x - 3y = 5xy ).
↪➡ 40x - 15y = 25xy..............(3).
→ From equation (2).
↪➡ 3 ( 6x - 5y = -2xy ).
↪➡ 18x - 15y = -6xy...............(4).
▶⏩ Now,
→ Substract in equation (3) and (4).
↪➡ ( 40x - 15y ) - ( 18x - 15y ) = ( 25xy ) - ( -6xy ).
↪➡ 40x - 15y - 18x + 15y = 25xy + 6xy.
↪➡ 22x = 31xy.
↪➡ y = 22x/31x.
↪➡ y = 22/31.
▶⏩ Put the value of ‘y’ in equation (1).
↪➡ 8x - 3(22/31) = 5xy.
↪➡8x - 66/31 = 5x(22/31).
↪➡ 8x - 110x/31 = 66/31.
↪➡ 138x/31 = 66/31.
↪➡ 138x = 66.
↪➡ x = 66/138.
↪➡ x = 33/69.
✔✔ Hence, the value of ‘x’ = 33/69.
and ‘y’= 22/31 ✅✅.
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
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