Question

solve each of the quadratic equations

4x2+4bx-(a2-b2)=0​

Answer 1

Step-by-step explanation:

4x² +4bx -(a² -b²) = 0

4x² +4bx -a² + b² =0

(2x)² + 2.(2x).b + b² -a² =0

(2x + b)² -a² = 0

Answer 2

Answer:

4x^2+4b^x-(a^2-b^2)=0

4x^2+4b^x-a^2+b^2=0

(2x)^2+2(2x)b+b^2-a^2=0

(2x+b)^2-a^2=0

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