Question

Solve each problem with solution and answer

Two cars leave Legaspi City and travel in opposite directions. Car A avarages 12 kph less than car B. After 3 hours, they must be atleast 396km apart. What is the miimum average rate of each car?

Help:(((

Answer 1

Answer:

A's avg speed x=360/6=60 kph

and B's avg speed=x+12=60+12=72 kph

Step-by-step explanation:

Let car A 's  speed=x kph

Then A's speed is 12 kph than B

so B's speed=x+12 kph

They travel in opposite direction

so total effective speed=x+x+12=2x+12

Total distance in 3 hrs

=3*(2x+12)=396 km

6x+36=396

6x=396-36=360

A's avg speed x=360/6=60 kph

and B's avg speed=x+12=60+12=72 kph