Question

Solve each sum by i) substitution method ii) elimination method iii)cross multiplication

Answer 1

Answer:

2x+3y = 13 and x-2y = -4

Given:

2x+3y = 13  …  (1)

x-2y = -4 …(2)

The equation (2) can be written as

x = 2y-4 … (3)

Now, in equation (1) eliminate the variable x by substituting the equation (3).

Hence, equation (1) becomes

2(2y-4) +3y = 13

Now, apply the distributive property for the above equation,

4y-8+3y = 13

Now, solve the above equation for the variable y

7y – 8 = 13

7y = 13+8

7y = 21

y= 21/7

y= 3

Hence, the value of y is 3.

Now, substituting y=3 in the equation (2), we get

x- 2(3) = -4

x – 6=-4

x = -4+6

x = 2

Therefore, the value of x is 2.

Hence, the solution for the system of linear equations is:

x = 2 and y=3

To check whether the obtained solution is correct or not, substitute the values of x and y in any of the given equations. 

Verification:

Use Equation (2) to verify the solution

x-2y = -4 

Now, substitute x= 2 and y=3

2-2(3) = -4

2-6= -4

-4=-4

Here, L.H.S = R.H.S

Hnece, the obtained solution is correct

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